Question

Gente me ajudem pfv preciso urgente

Answer 1

Resposta:

a) $\sqrt[3]{27} = \sqrt[3]{3*3*3}$

$\sqrt[3]{3*3*3} = 3$

b)

$\sqrt[3]{64} = \sqrt[3]{2^{2} *2^{2} *2^{2} } \\\\\\\\sqrt[3]{2^{6} } = 2^{2} = 4$

c)

$\sqrt[3]{343} = \sqrt[3]{7*7*7} \\\\\sqrt[3]{7*7*7} = 7$

d)

$\sqrt[3]{729} =\sqrt[3]{3^{2} *3^{2} *3^{2} } \\\\\sqrt[3]{3^{6} } = 3^{2} = 9$

OBS: Fatoraçao e so com números primos.