Question

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80-[22+(5×2-1)+6=

14÷2+[13-(4×2+1)]=

4×(10+20+15+30)=

(10×6+12×4+5×8)-40=

[6×(3×4-2×5)-4]+3×(4-2)-(10÷2)=

Answer 1

80-[22+(5×2-1)+6]
80-[22+(10-1)+6]
80-[22+9+6]
80-[22+15]
80-37
43



14÷2+[13-(4×2+1)]
14÷2+[13-(8+1)]
14÷2+[13-9]
14÷2+4
7+4
11




4×(10+20+15+30)
4×(30+45)
4×75
300




(10×6+12×4+5×8)-40
(60+48+40)-40
(108+40)-40
148-40
108




[6×(3×4-2×5)-4]+3×(4-2)-(10÷2)
[6×(12-10)-4]+3×(4-2)-(5)[6×2-4]+3×2-5
[12-4]+3×2-5
8+3×2-5
8+6-5
8+1
9