Question

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80-[22+(5×2-1)+6=

14÷2+[13-(4×2+1)]=

4×(10+20+15+30)=

(10×6+12×4+5×8)-40=

[6×(3×4-2×5)-4]+3×(4-2)-(10÷2)=

Answer 1

80-[22+(5×2-1)+6=80-[22+(10-1)+6= 80-[22+9+6]=80-37==> 43
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14÷2+[13-(4×2+1)]= 7+[13-(8+1)]=7+[13-9]= 7 + 4 =  11
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4×(10+20+15+30)= 4×(75)= 300
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(10×6+12×4+5×8)-40= (60+48+40)-40= 148-40 = 108
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[6×(3×4-2×5)-4]+3×(4-2)-(10÷2)= [6×(12-10)-4]+3×(2)-5=

 [6×(2)-4]+6-5=  [

[12-4]+1=  8+1 ==> 9