Matemática, perguntado por elizangelamcsantos, 11 meses atrás

gente me ajudem hoje tem recuperação




a)3x/2+4=x- 5x+2/2
b)x/4+=3x-1/3
c)x/2+5 =x+x/3​

Soluções para a tarefa

Respondido por btardin
1

Resposta:

a)

x=-\frac{6}{11}

b)

x=\frac{4}{33}

c)

x=-6

Explicação passo-a-passo:

a)

\frac{3x}{2}+4=x- 5x+\frac{2}{2}\\\\(2)\frac{3x}{2}+(2)4=(2)x- 5x(2)+\frac{2}{2}(2)\\\\3x+8=2x-10x+2\\3x=-8x-8+2\\3x+8x=-6\\11x=-6\\\\x=-\frac{6}{11}

b)

\frac{x}{4}=3x-\frac{1}{3}\\\\(4)\frac{x}{4}=(4)3x-\frac{1}{3}(4)\\\\\\x=12x-\frac{4}{3}\\\\x-12x=-\frac{4}{3}\\-11x=-\frac{4}{3}\\\\11x = \frac{4}{3}\\\\x= \frac{\frac{4}{3}}{11}\\\\x=\frac{4}{3}\cdot\frac{1}{11}\\\\x=\frac{4}{33}

c)

\frac{x}{2}+5=x+\frac{x}{3}\\\\\frac{x}{2}-x-\frac{x}{3}=-5\\\\\frac{x(3)}{2(3)}-x-\frac{x(2)}{3(2)}=-5\\\\\frac{3x}{6}-\frac{2x}{6}-x=-5\\\\(6)\frac{3x}{6}-\frac{2x}{6}(6)-x(6)=-5(6)\\\\3x-2x-6x=-30\\5x=-30\\\\x=-\frac{30}{5}\\\\x=-6

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