Question

gente me ajudem fassam a 121 pra mim

Answer 1

$a)5^7*5^{-5}+4^3\to\\\\ 5^{7+(-5)}+4^3\to\\\\ 5^{7-5}+4^3\to\\\\ 5^2+4^3\to\\\\ 25+64\to\\\\89\\\\\\\\ b)6^8:6^5-3^2*3^4\to\\\\ 6^{8-5}-3^{2+3}\to\\\\ 6^3-3^5\to\\\\ 216-243\to\\\\ -27\\\\\\\\ c) (5-9)^3*(12^{10}:12^9)*(-4)^{-2}\to \\\\ (-4)^3*(12^{10-9})* (\frac{1}{4} )^2\to \\\\ (-4)^3*(12^{1})* (\frac{1}{4} )^2\to\\ \\ -64*12* \frac{1}{16} \to \\\\ \frac{-768}{16} \to\\\\ -48$




$d)9^3*3^{-5}+(7^2)^7:7^{14}\to\\\\ 9^3* \frac{1}{3} ^{5}+(7^{2*7}):7^{14}\to \\\\ 9^3* \frac{1}{3} ^{5}+(7^{14}):7^{14}\to\\\\ 9^3* \frac{1}{3} ^{5}+7^{14-14}\to \\\\ 9^3* \frac{1}{3} ^{5}+7^0\to\\\\ 729* \frac{1}{243} +1\to \\\\ \frac{729}{243} +1\to\\\\ 3+1\to\\\\ 4$




$e)6*2^5+( \frac{1}{2} )^{-2}*2^2+[(-0,1)^{-1}]^3\to \\\\ 6*2^5+(2)^{2}*2^2+[(- \frac{10}{100} )^{-1*3}]\to \\\\ 6*2^5+2^{2}*2^2+[(- \frac{10}{100} )^{-3}]\to\\ \\ 6*2^5+2^{2}*2^2+[(- \frac{100}{10} )^{-3}]\to\\ \\ 6*32+4*4+(- \frac{1000000}{1000} )\to \\ \\ 6*32+4*4+(- 1000 )\to \\\\ 6*32+4*4-1000 \to \\\\ 192+16-1000\to \\\\ 208-1000\to \\\\ -792$



Espero ter ajudado...