Question

gente me ajudem a resolver esses polinomios pfv ! :

a) (2x +2) . (3x -4)
B) (3 - 2x) . (5 + x)
C) (3a + a ) . (a + a)

Answer 1

a) (2x +2) . (3x -4)
aplica-se a distributiva
6x - 8x + 6x -8 = 0
12x - 8x = +8
4x = 8
x = 8/4
x = 2

B) (3 - 2x) . (5 + x)
aplica-se a distributiva

15 + 3x - 10x - 2x²
- 2x² - 7x + 15 = 0
Δ = b² - 4.a.c
Δ = 49 - 4.(-2).(+15)
Δ = 49 + 120
Δ = √169
Δ = 13

x = -b ⁺₋ √Δ
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
2.a

x = + 7 +- 13
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-4

+ = 20 / -4 = -5
- = - 6 / -4 = 1.5

C) (3a + a ) . (a + a)
3a² + 3a² + a² + a²
6a² + a² + a² = 8a²
a² = 8
a = √8