Question

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1) Determine [(a²b³)² x (a³b²)] para a = 5 e b = -9

Answer 1

[(a²b³)² x (a³b²)]

A = 5

B = -9

5² = 5 × 5 = 25

-9³ = -9 × -9 × -9 = −729

25/729

25² = 25 × 25 = 625

729² = 729 × 729 = 531.441

625 × 531.441 = 332.150.625

5³ = 5 × 5 × 5 = 125

-9² = -9 × -9 = 81

125 × 81 = 10.125

332.150.625 × 10.125 = 3.363.025.078.125

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