Gente Me ajudam por favor
(x-4).(x-2) =
(3x-12).(3x-6) =
(3y+3).(3y+2) =
(30y+30).(30y+20) =
(x+4).(x+2) =
(2x+8).(2x+4) =
(x-1).(x-4) =
(3x-3).(3x-12) =
Soluções para a tarefa
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(x-4).(x-2) =x²-2x-4x+8=x²-6x+8
(3x-12).(3x-6) =9x²-18x-36x+72=9x²-54x+72
(3y+3).(3y+2) =9y²+6y+9y+6=9y²+15y+6
(30y+30).(30y+20) =90y²+60y+90y+60=90y²+150y+60
(x+4).(x+2) =x²+2x+4x+8=x²-6x+8
(2x+8).(2x+4) = 4x²+8x+16x+32=4x²+24x+32
(x-1).(x-4) =x²-4x-x+4=x²-5x+4
(3x-3).(3x-12) =9x²-36x-9x+36=9x²-45x++36
(3x-12).(3x-6) =9x²-18x-36x+72=9x²-54x+72
(3y+3).(3y+2) =9y²+6y+9y+6=9y²+15y+6
(30y+30).(30y+20) =90y²+60y+90y+60=90y²+150y+60
(x+4).(x+2) =x²+2x+4x+8=x²-6x+8
(2x+8).(2x+4) = 4x²+8x+16x+32=4x²+24x+32
(x-1).(x-4) =x²-4x-x+4=x²-5x+4
(3x-3).(3x-12) =9x²-36x-9x+36=9x²-45x++36
Thalytasantana1:
Obrigada <3
Olá Bia
me ajudam
(x+2).(x-1) =
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