Matemática, perguntado por nicollyaraujo2710, 3 meses atrás

gente me ajuda pfv e pra amanhã
 {x}^{2}  = 9 \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  x =
e \: de \: potencia \:

Soluções para a tarefa

Respondido por PerguntadosLaTex
3

 \bf\large{\underline{\qquad \qquad\qquad \qquad \qquad \qquad \qquad \quad }} \\ \\

Resposta correta:

  •  \large~~{~~\boxed{\boxed{\begin{array}{lr}\displaystyle{\green{~ S=\{-3;3\} ~ }}\end{array}}}} \\ \\

\underline{\underline{\overline{\overline{\begin{gathered}\boxed{\begin{array}{l} \\\sf\begin{gathered}\large\textsf{\textbf{\underline{Calculo:}}}\end{gathered} \\\ ~ \\\  {\large{\displaystyle{ {x}^{2} = 9 }}} & \\  \\  {\large{\displaystyle{x =  \pm \sqrt{9} }}} & \\  \\ { \large{\displaystyle{x =  \pm 3}}}&\\ \\  \\ \quad {\Large{\displaystyle{x =  -3 }}}& \\  \\ \quad {\Large{\displaystyle{x = 3 }}}\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\end{array}}\end{gathered}}}}} \\ \\

 ~~~~~~~~~~~\bf Att.

 {\Huge{\underline{\green{\mathbb{P}}E\green{\mathbb{R}}G\green{\mathbb{U}}N}}} \\  { \Huge{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: {{\underline{\green{ T}\mathbb{A}\green{D}\mathbb{O}\green{S}}}}}} \\ \\

 \bf\large{\underline{\qquad \qquad\qquad \qquad \qquad \qquad \qquad \quad }}

Respondido por jean318
1

Resposta:

Explicação passo a passo:

x^{2} =9

x=\pm\sqrt{9}

x=\pm3

S=\{-3;3\}

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