Question

Gente, alguém poderia me explicar como se resolve essa equação abaixo?

4(4n-2)(2+4n)=(8n-5)(8n+4)+12​

Answer 1

$\mathsf{4(4n-2)(2+4n)=(8n-5)(8n+4)+12}\\\mathsf{4(8n+16n^2-4-4n)=64n^2+32n-40n-20+12}\\\mathsf{32n+64n^2-16-16n=64n^2+32n-40-20+12}$

$\mathsf{64n^2-64n^2+32n-32n-16n=16-40-20+12}\\\mathsf{-16n=-32\times(-1)}\\\mathsf{16n=32}\\\mathsf{n=\dfrac{32}{16}}$

$\huge\boxed{\boxed{\boxed{\mathsf{n=2}}}}$