Question

gente alguem pode me ajudar nesse exercício de álgebra. nao consigo fazer. alguem me ajuda

Answer 1

$A= \left[\begin{array}{cc}4&1\\-3&2\end{array}\right] \\ \\ 3A = \left[\begin{array}{cc}3*4&3*1\\3*(-3)&9*2\end{array}\right] \\ \\ 3A= \left[\begin{array}{cc}12&3\\-9&6\end{array}\right]$

$B= \left[\begin{array}{cc}-6&2\\4&-5\end{array}\right] \\ \\ 5B= \left[\begin{array}{cc}-30&10\\20&-25\end{array}\right] \\ \\ 3A+5B=$
$\left[\begin{array}{cc}12&3\\-9&6\end{array}\right]+ \left[\begin{array}{cc}-30&10\\20&-25\end{array}\right] = \left[\begin{array}{cc}-18&13\\-4&10\end{array}\right]$
******************************************************************
$]2A= \left[\begin{array}{cc}8&2\\-6&4\end{array}\right] \\ \\ 4B= \left[\begin{array}{cc}-24&8\\16&-20\end{array}\right] \\ \\ 2A-4B = \left[\begin{array}{cc}32&-6\\-22&24\end{array}\right]$
******************************************************************
$(A+B) = A= \left[\begin{array}{cc}4&1\\-3&2\end{array}\right]+\left[\begin{array}{cc}-6&2\\4&-5\end{array}\right] = \left[\begin{array}{cc}-2&-1\\1&-3\end{array}\right] \\ \\ (A+B)^{t} = \left[\begin{array}{cc}-2&1\\-1&-3\end{array}\right]$