Question

GENTE ALGUÉM ME AJUDA PFV

Resolva as potencias:

a) ( -9)²

b) ( - 2)³

c) (+10)⁴

d) ( - 6)³​

Answer 1

Resposta:

$a) (-9)^{2} = -9 . -9 = +81\\\\b) (-2)^{3} = -2 . -2 . -2 = -8\\\\c)(+10)^{4} = +10 . +10. +10 . +10= +10000\\\\d)(-6)^{3}= -6 . -6 . -6= -216$