Gente ajuda PF... E 9 ano
Anexos:
Soluções para a tarefa
Respondido por
0
Onwwwwwwt! :3
Resolução:
2^-3 + 3^-2 - ( 1/2 )³
( 1/2 )³ + ( 1/3 )² - ( 1/8 )
1/8 + 1/9 - 1/8
1/9 - 1/8 + 1/8
1/9 + 0
1/9
Espero ter ajudado! ✌
Resolução:
2^-3 + 3^-2 - ( 1/2 )³
( 1/2 )³ + ( 1/3 )² - ( 1/8 )
1/8 + 1/9 - 1/8
1/9 - 1/8 + 1/8
1/9 + 0
1/9
Espero ter ajudado! ✌
lorrainegabi12:
Mais VC nn pode fazer o resto nn pf
Respondido por
1
Ola Lorraine
1)
2^-3 = 1/8
3^-2 = 1/9
(1/2)^3 = 1/8
1/8 + 1/9 - 1/8 = 1/9
2)
a = 4/3, b = -2
a^-2 = 9/16 , b^-4 = 1/16
2*9/16 + 1/16 = 19/16
3)
a) 5^-2*10 = 10/25 = 2/5
b) 8/2^-1 = 16
c) 1/9*(8/64)^-3 = (1/9)*512 = 512/9
d) 1/5 + 1/10 = 3/10
e) 1/32 - 1/8 = 1/32 - 4/32 = -3/32
f) (1/9 + 1/6)^-2 = (15/54)^-2 = (54/15)^2 = (18/5)^2 = 324/25
g) (125/100)^-2 = (5/4)^-2 = (4/5)^2 = 16/25
4)
a = 9 - 1/16 = 143/16
b = (1/3 + 1/2)-^3 = (5/6)^-3 = (6/5)^3 = 216/125
a^-2 = (16/143)^2 = 256/20449
6b = 6*216/125 = 1296/125
a^-2/6b = (256/20449)/(1296/125) = 2000/1656369
1)
2^-3 = 1/8
3^-2 = 1/9
(1/2)^3 = 1/8
1/8 + 1/9 - 1/8 = 1/9
2)
a = 4/3, b = -2
a^-2 = 9/16 , b^-4 = 1/16
2*9/16 + 1/16 = 19/16
3)
a) 5^-2*10 = 10/25 = 2/5
b) 8/2^-1 = 16
c) 1/9*(8/64)^-3 = (1/9)*512 = 512/9
d) 1/5 + 1/10 = 3/10
e) 1/32 - 1/8 = 1/32 - 4/32 = -3/32
f) (1/9 + 1/6)^-2 = (15/54)^-2 = (54/15)^2 = (18/5)^2 = 324/25
g) (125/100)^-2 = (5/4)^-2 = (4/5)^2 = 16/25
4)
a = 9 - 1/16 = 143/16
b = (1/3 + 1/2)-^3 = (5/6)^-3 = (6/5)^3 = 216/125
a^-2 = (16/143)^2 = 256/20449
6b = 6*216/125 = 1296/125
a^-2/6b = (256/20449)/(1296/125) = 2000/1656369
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