Question

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resolva o sistema
2x+3y=14
-x+5y=-7

Answer 1

{ 2x + 3y =14
{ -x  + 5y= -7  .(2)

-2x +10y = - 14
 2x +  3y =   14  
  0  + 13y= 0
             y =  0       y = 0
                   13

2x + 3y = 14
2x +3 . 0 =14
2x +0 =14
2x = 14
  x= 14 
        2
x = 7                            S= { 7 ; 0 }

Answer 2

$\left \{ {{2X+3Y=14(I)} \atop {-X+5Y=-7(II)}} \right. \\ \\ Y= \frac{-7+X}{5} \\ \\ (I)2X+3* \frac{-7+X}{5} =14 \\ 2X \frac{-21+3X}{5}=14 \\ \frac{10X}{5} \frac{-21}{5} \frac{+3X}{5}= \frac{70}{5} \\ 10X-21+3X=70 \\ 13X=91 \\ X= \frac{91}{13} \\ X=7 \\ \\ Y= \frac{-7+7}{5} \\ Y=0$