Question

Galera... O valor de (log 125 + log 4 + log 2) + (log 2000 - log 20) é????

Answer 1

$\rightarrow\log125+\log4+\log2=\log125\cdot4\cdot2=\log1000=3$

$\rightarrow\log2000-\log20=\log \frac{2000}{20}=\log100=2$

$\rightarrow3+2=5$