Matemática, perguntado por massoterapiabea, 10 meses atrás

g)3 - (1/2 - 1/3) =

h) - 5/4 - ( - 3 - 1/3)=

i)- 4/9 - ( - 3 - 2/3)=

j)7/9 + 5/12 - 1/6 =

k) 3 + ( 5/4 - 1/2 )=

l) - 3/5 + 6/5 - 1/3=

Soluções para a tarefa

Respondido por crmacena
1

Resposta:

g)3 - (1/2 - 1/3) =

3-(\frac{1}{2} -\frac{1}{3} )=  3-(\frac{3}{6} -\frac{2}{6} )=  3-(\frac{3-2}{6}  )=  3-\frac{1}{6} =  \frac{18}{6} -\frac{1}{6} =\frac{18-1}{6} =\frac{17}{6}

h) - 5/4 - ( - 3 - 1/3)=

-\frac{5}{4} -(-3-\frac{1}{3} )=   -\frac{5}{4} -(-\frac{9}{3}-\frac{1}{3} )=  -\frac{5}{4} -(\frac{-9-1}{3}} )=  -\frac{5}{4} -(\frac{-10}{3}} )=

-\frac{5}{4} +\frac{10}{3}} =  -\frac{15}{12} +\frac{40}{12}} =  \frac{-15+40}{12} =  \frac{25}{12}

i)- 4/9 - ( - 3 - 2/3)=

-\frac{4}{9} -(-3-\frac{2}{3}) =  -\frac{4}{9} -(-\frac{9}{3} -\frac{2}{3}) =  -\frac{4}{9} -(\frac{-9-2}{3}) =  -\frac{4}{9} -(\frac{-11}{3}) =

-\frac{4}{9}+\frac{11}{3} =  -\frac{4}{9}+\frac{33}{9} =  \frac{-4+33}{9} =  \frac{29}{9}

j)7/9 + 5/12 - 1/6 =

\frac{7}{9} +\frac{5}{12} -\frac{1}{6} =  \frac{28}{36} +\frac{15}{36} -\frac{6}{36} =  \frac{28+15-6}{36} =  \frac{37}{36}

k) 3 + ( 5/4 - 1/2 )=

3+(\frac{5}{4} -\frac{1}{2} )=  3+(\frac{5}{4} -\frac{2}{4} )=  3+(\frac{5-2}{4} )=  3+\frac{3}{4}=  \frac{12}{4} +\frac{3}{4}=  \frac{12+3}{4}= \frac{15}{4}

l) - 3/5 + 6/5 - 1/3=

-\frac{3}{5} +\frac{6}{5} -\frac{1}{3} =  -\frac{9}{15} +\frac{18}{15} -\frac{5}{15} =  \frac{-9+18-5}{15}  =  \frac{4}{15}

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