Question

(fuvest-sp)se log2=0,301 e log3=0,477 o valor de log 1,8 é

Answer 1

$\log2\approx0,301\\\log3\approx0,477\\\\\log1,8\\\log(\frac{18}{10}}\\\log18-\log10\\\log(2.3.3)-1\\\log2+\log3+\log3-1\\0,301+0,477+0,477-1\approx\boxed{0,255}$