Matemática, perguntado por Millysilva26, 1 ano atrás

(Fuvest-sp) : Se f(X) = 2x²-3x+1 calcule f(raix quadrada de 2/3)?

Soluções para a tarefa

Respondido por Usuário anônimo
8
Boa noite!

Solução!

f(x)=2 x^{2} -3x+1\\\\\\ f\bigg( \dfrac{ \sqrt{2} }{3}\bigg)=2\bigg( \dfrac{ \sqrt{2} }{3}\bigg)^{2}  -3\bigg( \dfrac{ \sqrt{2} }{3}\bigg)+1\\\\\\\\\\ f\bigg( \dfrac{ \sqrt{2}}{3}\bigg)=2\bigg( \dfrac{2}{9}\bigg) -\bigg( \sqrt{2} \bigg)+1\\\\\\\\\\\ f\bigg( \dfrac{ \sqrt{2}}{3}\bigg)=\bigg( \dfrac{4}{9}\bigg) -\bigg( \sqrt{2} \bigg)+1\\\\\\\\\\ f\bigg( \dfrac{ \sqrt{2}}{3}\bigg)= \dfrac{4 -9 \sqrt{2} +9}{9} \\\\\\\\\\\ \boxed{f\bigg( \dfrac{ \sqrt{2}}{3}\bigg)= \dfrac{13 -9 \sqrt{2} }{9}}

Boa noite!
Bons estudos!



Millysilva26: Obrigado
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