Question

(Fuvest-sp) : Se f(X) = 2x²-3x+1 calcule f(√2/3)?

Answer 1

Temos f(x) = 2x² – 3x + 1.

Só precisamos substituir x por √2/3:

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) = 2 \cdot \left( \frac{\sqrt[]{2}}{3} \right)^2 - 3 \cdot \frac{\sqrt[]{2}}{3} + 1$

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) = 2 \cdot \left( \frac{2}{9} \right) - \not3 \cdot \frac{\sqrt[]{2}}{\not3} + 1$

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) = \frac{4}{9} - \sqrt[]{2} + 1$

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) = \frac{4}{9} - \frac{9 \hspace{0,07cm} \sqrt[]{2} }{9} + \frac{9}{9}$

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) = \frac{4 + 9 - 9 \hspace{0,07cm} \sqrt[]{2} }{9}$

$\displaystyle f \left( \frac{\sqrt[]{2}}{3} \right) =\frac{5 - 9 \hspace{0,07cm} \sqrt[]{2}}{9}$

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Answer 2

Resposta:

Explicação passo-a-passo: