Question

(fuvest-SP)calcule:
$8 {}^{ \frac{1}{3} } + 9 {}^{0.5}$​

Answer 1

Explicação passo-a-passo:

$8^{1\over3}+9^{0,5}=\\ \\ \sqrt[3]{8} +9^{5\over10}=\\ \\ \sqrt[3]{2^3} +9^{1\over2}=\\ \\ 2+\sqrt{9} =\\ \\ 2+3=5$

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ou assim

$(2^3)^{1\over3}+(3^2)^{1\over2}=\\ \\ 2^{3\over3}+3^{2\over2}=\\ \\ 2^1+3^1=\\ \\ 2+3=5$