Question

funcoes
$( \frac{4}{9}. \frac{9}{10} - \frac{1}{15} ) ( \frac{3}{2} + \frac{5}{8} . \frac{4}{5} )$
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Answer 1

Explicação passo-a-passo:

$({\not4^2\over\not9}.{\not9\over\not10_5}-{1\over15})({3\over2}+{\not5\over\not8_2}.{\not4\over\not5})=\\ \\ ({2\over5}-{1\over15})({3\over2}+{1\over2})=\\ \\ ({6-1\over15})({4\over2})=\\ \\ ({5\over15})(2)={10\over15}={2\over3}$