Question

função quadrática f(x) = x² - 5x +6, calcule f(1) + f(2) -f(3) -f(4)

Answer 1

F(1) = 1² - 5.1 + 6 = 1 - 5 + 6 = 2
F(2) = 2² - 5.2 + 6 = 4 - 10 + 6 = 0
F(3) = 3² - 5.3 + 6 = 9 - 15 + 6 = 0
F(4) = 4² - 5.4 + 6 = 16 - 20 + 6 = 2

F(1) + F(2) - F(3) - F(4) =
2 + 0 - 0 - 2 = 0

Answer 2

f(1)=1-5+6=2
f(2)=4-10+6=0
f(3)=9-15+6=0
f(4)=16-20+6=2
f(1)+f(2)-f(3)-f(4)
2+0-0-2=0