Question

Função quadrática determine as raízes f(x)=x2+6x+9

Answer 1

x²-Sx+ P =0
x+x'= -6
x*x'= 9

x = x' = -3

Answer 2

f(x) = x² + 6x + 9

Igular a 0 para achar as raízes:
x² + 6x + 9 = 0

a = 1
b = 6
c = 9

∆ = b² - 4ac
∆ = 6² - 4.1.9 = 36 - 36 = 0

x = -b +- √∆
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2a

x = -6 +- √0
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2.1

x = -6 +- 0
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2


x¹ = -6 + 0/2 = -6/2 = -3
x² = -6-0/2 = -6/2 = -3