Question

funçao f:R →R é definida por f(x) = (m²-4). x² +(m-2). x-10.considere m= 3.calcue os valores de f(0),f(2),f(-3)

Answer 1

Olá!!!

Resolução!

m = 3

f ( x ) = ( m² - 4 )x² + ( m - 2 )x - 10
f ( x ) = ( 3² - 4 )x² + ( 3 - 2 )x - 10
f ( x ) = ( 9 - 4 )x² + x - 10
f ( x ) = 5x² + x - 10

***

• f ( 0 )

f ( x ) = 5x² - x - 10
f ( 0 ) = 5 • ( 0 )² - ( 0 ) - 10
f ( 0 ) = 5 • 0 - 0 - 10
f ( 0 ) = 0 - 0 -10
f ( 0 ) = - 10

• f ( 2 )

f ( x ) = 5x² - x - 10
f ( 2 ) = 5 • ( 2 )² - ( 2 ) - 10
f ( 2 ) = 5 • 4 - 2 - 10
f ( 2 ) = 20 - 2 - 10
f ( 2 ) = 20 - 12
f ( 2 ) = 8

• f ( - 3 )

f ( x ) = 5x² - x - 10
f ( - 3 ) = 5 • ( - 3 )² - ( - 3 ) - 10
f ( - 3 ) = 5 • 9 - ( - 3 ) - 10
f ( - 3 ) = 45 - ( - 3 ) - 10
f ( - 3 ) = 45 + 3 - 10
f ( - 3 ) = 48 - 10
f ( - 3 ) = 38

Espero ter ajudado!!!

Answer 2

Olá!!!

Resolução!

m = 3

f ( x ) = ( m² - 4 )x² + ( m - 2 )x - 10

f ( x ) = ( 3² - 4 )x² + ( 3 - 2 )x - 10

f ( x ) = ( 9 - 4 )x² + x - 10

f ( x ) = 5x² + x - 10

***

• f ( 0 )

f ( x ) = 5x² - x - 10

f ( 0 ) = 5 • ( 0 )² - ( 0 ) - 10

f ( 0 ) = 5 • 0 - 0 - 10

f ( 0 ) = 0 - 0 -10

f ( 0 ) = - 10

• f ( 2 )

f ( x ) = 5x² - x - 10

f ( 2 ) = 5 • ( 2 )² - ( 2 ) - 10

f ( 2 ) = 5 • 4 - 2 - 10

f ( 2 ) = 20 - 2 - 10

f ( 2 ) = 20 - 12

f ( 2 ) = 8

• f ( - 3 )

f ( x ) = 5x² - x - 10

f ( - 3 ) = 5 • ( - 3 )² - ( - 3 ) - 10

f ( - 3 ) = 5 • 9 - ( - 3 ) - 10

f ( - 3 ) = 45 - ( - 3 ) - 10

f ( - 3 ) = 45 + 3 - 10

f ( - 3 ) = 48 - 10

f ( - 3 ) = 38

Espero ter ajudado!!!