Question

função exponencial 27^2x-1=9^x+1

Answer 1

$27^{2x-1}=9^{x+1}\\ \\ 3^{3(2x-1)}=3^{2(x+1)}\\ \\ 3(2x-1)=2(x+1)\\ \\ 6x-3=2x+2\\ \\ 6x-2x=2+3\\ \\ 4x=5\\ \\ x=\frac{5}{4}$