Question

funçao do 2° grau (vertice x,v,y,v)
a) x²-4x=0
b) 2x²-128=0

Answer 1

a) ∆ = b² - 4ac
∆ = 16 - 4 × 1 × 0
∆ = 16

Xv = -b / 2a
Xv = 4 / 2 × 1
Xv = 4 / 2
Xv = 2

Yv = -∆ / 4a
Yv = -16 / 4 × 1
Yv = -16 / 4
Yv = -4


b) ∆ = 0 - 4 × 2 × (-128)
∆ = 512

Xv = 0 / 2 × 2
Xv = 0 / 4
Xv = 0

Yv = -512 / 4 × 2
Yv = -512 / 8
Yv = -64

a) (2,-4)
b) (0,-64)

Espero ter ajudado!!!