Question

Fração.

Preciso da resolução.

Answer 1

Explicação passo-a-passo:

Expressão numérica:

$\mathsf{\left[\frac{3.\Big(-\frac{3}{4}\Big)^{-2}+6.\Big(\frac{3^{-1}}{4}\Big)-4}{7.\Big(\frac{-3}{4}\Big)^{-1}+2} \right]^{-1}+4}$

$\mathsf{\left[ \frac{3.\Big(-\frac{4}{3} \Big)^2 + 6.\Big( \frac{\frac{1}{3}}{4} \Big)-4 }{7.\Big(-\frac{4}{3} \Big)+2 } \right]^{-1} + 4 }$

$\mathsf{ \left[ \frac{\cancel{3}.\frac{16}{\cancel{9}} + \cancel{6}.\frac{1}{\cancel{12}}-4}{-\frac{28}{3}+2} \right]^{-1}+4 }$

$\mathsf{ \left[ \frac{\frac{16}{3}+\frac{1}{2}-4}{-\frac{28+6}{3}} \right]^{-1}+4}$

$\mathsf{ \Big( \frac{ \frac{32}{6}+\frac{3}{6}-\frac{24}{6} }{-\frac{22}{3} } \Big)^{-1}+4 }$

$\mathsf{ \Big( \frac{\frac{11}{6}}{-\frac{22}{3}} \Big)^{-1}+4 }$

$\mathsf{ \Big(\frac{11}{\cancel{6}}.-\frac{\cancel{3}}{22} \Big)^{-1}+4}$

$\mathsf{ \Big(\frac{1}{2}.-\frac{1}{2} \Big)^{-1} + 4 =}$

$\mathsf{\Big(-\frac{1}{4} \Big)^{-1}+4 = }$

$\boxed{\mathsf{(-4)+4=0}}}}$ $\checkmark$

Espero ter ajudado bastante!)