Question

\frac{3^{x+2}+3^{x+1}}{3^{x-1} }

Answer 1

$\frac{ {3}^{x + 2} + {3}^{x + 1} }{ {3}^{x - 1} } = \frac{ {3}^{x}. {3}^{2} + {3}^{x}.3}{ \frac{ {3}^{x} }{3} } = \frac{ \cancel{{3}^{x} }(9 + 3)}{ \frac{1}{3}. \cancel{{3}^{x}} }$

$\mathsf{\frac{12}{ \frac{1}{3} } = 12 \times 3 = 36}$