Question

Fórmula de delta (1-x)(5+2x)=5

Answer 1

(1 - x ) (5 + 2 x) = 5
5 + 2 x - 5 x - 2 x² = 5
-2 x² - 3 x + 5 = 5
2 x² - 3 x + 5 - 5 = 0
2 x² - 3 x = 0
x(2 x - 3 ) = 0
x = 0
2 x - 3 = 0
2 x = 3
x = 3/2
s = {0 ; 3/2}

ou
Δ = b² - 4.a.c
Δ = (-3)² - 4 . 2 . 0
Δ = 9 - 8 . 0
Δ = 9 - 0
Δ = 9 ⇒√9 = 3
x = - b + ou - 3/2.a
x = -(-3) +3/2
x= 3 + 3/2 ⇒6/2 = 3
x = 3 - 3/2
x = 0/2
x = 0
S ={0 ; 3 }