Question

Fórmula de Bháskara -x²-8x-15=0
Como resolver?

Answer 1

Boa tarde,

Δ = b² - 4 . a .c (b = -8 ; a = -1; c = -15)

Δ = (-8)² - 4. (-1). (-15)

Δ = 64 - 60

Δ = 4

X = $\frac{-b +- RaizDelta}{2.a}$

X = -(-8) +- √4 / 2. (-1)

X = 8 +- 2 / -2

x1 = 8 +2 / -2 = 10 / -2 = -5

x2 = 8 -2 / -2 = 6/-2 = -3