Question

formula de bhaskara e raizes -2x elevado a 2+7x-3=0

Answer 1

$delta = (7)^{2} - 4.( - 2).( - 3) \\ delta = 49 - 24 \\ delta = 25 \\ \\ x = \frac{ - 7 + 5}{ - 4} = \frac{ - 2 \div 2}{ - 4 \div 2} = \frac{1}{2} \\ x = \frac{ - 7 - 5}{ - 4} = \frac{ - 12}{ - 4} = 3$

Answer 2

-2x^2 + 7x - 3=0 (-1)

2x^2 - 7x + 3 = 0

a = 2; b = - 7; c = 3

∆ = b^2-4ac

∆ = (-7)^2 - 4.2.3

∆ = 49 - 24

∆ = 25

x = [ - b +/- √∆]/2a

x = [- (-7( +/- √25]/2.2

x = [ 7 +/- 5]/4

x' = (7+5)/4 = 12/4 = 3

x" = (7-5)/4 = 2/4 (:2)/(:2) = 1/2

R.: x' = 3 ; x" = 1/2