Question

Formula de Bhaskara
4x² -3x-1=0

Answer 1

$4x^2 - 3x - 1 = 0$

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=4, b=−3, c=−1

Δ=b²−4ac
Δ=(−3)2−4*(4)*(−1)
Δ=9+16
Δ=25

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-3) \pm \sqrt{25}}{2*4} \\ \\ \\ x = \dfrac{3 \pm 5}{8} \\ \\ \\ x' = \dfrac{3 + 5}{8} \\ \\ x' = \dfrac{8}{8} \\ \\ \\ x' = 1 \\ \\ \\ x'' = \dfrac{3 - 5}{8} \\ \\ \\ x'' = \dfrac{-2}{8} \\ \\ \\ x'' = \dfrac{-1}{4}$


S = {$1, \ -\dfrac{1}{4}$}