Question

Formula de bhaskara?
-2x²+10x-12=0

Answer 1

-2x² + 10x - 12 = 0

a = -2; b = 10; c = -12

Delta:
Δ = b² - 4ac
Δ = 10² - 4 * (-2) * (-12)
Δ = 100 - 96
Δ = 4
        Bhaskara:
        x = - b ± √Δ / 2a
        x = - 10 ± √4 / 2 * (-2)
        x = - 10 ± 2 / -4
        x' = - 10 - 2 / -4 = -12 / -4 = 3
        x'' = - 10 + 2 / -4 = -8 / -4 = 2

Espero ter ajudado. Valeu!

Answer 2

Resolvendo Δ
Δ=b²-4ac
Δ=10²-4×(-2)×(-12)
Δ=100+8×(-12)
Δ=100-96
Δ=4

Fórmula

x=-b+-√Δ/2a
x=-10+-√4 / 2×(-2)
x=-10+-2/-4
x1=-10-2/-4=-12/-4=3
x2=-10+2/-4=-8/-4=2