Question

formula de baskara
X elevado ao expoente 2 menos 5x + 1 = 0 ​

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-5x+1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-5~e~c=1\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(1)(1)=25-(4)=21\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{21}}{2(1)}=\frac{5-\sqrt{21}}{2}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{21}}{2(1)}=\frac{5+\sqrt{21}}{2}\\\\S=\{\frac{5-\sqrt{21}}{2},~\frac{5+\sqrt{21}}{2}\}$