Question

formula de baskara com explicaçao x ao quadrado -x-1=

Answer 1

x^{2}-x-1=0
a→coeficiente de x^{2}
b→coeficiente de x
c→termo independente

Sendo assim temos:

a=1 b= -1 c= -1

\delta=b^{2}-4ac
\delta= -1^{2}-4(1)(-1)
\delta=1+4
\delta=5

x= \frac{-b+-\sqrt{\delta}} {2a}
x= \frac{-(-1)+-\sqrt{5}} {2(1)}

x'=\frac{1+\sqrt{5}} {2}
x"=\frac{1-\sqrt{5}} {3}

Answer 2

Ola!!

Têm-se a equação:

${\color{blue}{x^2-x-1=0}}$

$Coeficientes:\left\{\begin{array}{cc}a=1\\b=-1\\c=-1\\\end{array}\right$

Lembrando que:

$\Delta=b^2-4*a*c$

$\Delta=(-1)^2-4*1*(-1)$

$\Delta=1+4$

$\Delta=5$

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2*a}}}}}}$

$x_{1,2}=\frac{1\pm\sqrt{5}}{2*1}$

$x_{1,2}=\frac{1\pm\sqrt{5}}{2}$

Dúvidas??Comente!!