Question

formula de baskara 6(2x-3)^=2(5x+8)^2? socorroooooooooooooooooo

Answer 1

$6(2x-3)^2=2(5x+8)^2\\ 6(4x^2-12x+9)=2(25x^2+80x+64)\\ 3(4x^2-12x+9)=25x^2+80x+64\\ 12x^2-36x+27=25x^2+80x+64\\ 13x^2+116x+37=0\\ \\\Delta=(116)^2-4.13.37\\ \\ \Delta=13456-1924\\ \\ \Delta=11532\\ \\ x=\frac{-116\pm\sqrt{11532}}{26}\\ \\ x=\frac{-116\pm62\sqrt3}{26}\\ \\ x=\frac{58\pm31\sqrt3}{13}$