Question

Formula de Báskara

4x²+11x-3=0

Answer 1

4x²+11x-3=0

a=4
b=11
c= -3

/// /\=b²-4.a.c
\\\ x= -b + - √/\

/\=11²-4.4.(-3)
/\=121-16.(-3)
/\=121+48
/\=169

x'= -11+√169 /2.4
x'= -11+13 /8
x'= 2/8
x'= 1/4

x"= -11-√169 /2.4
x"= -11-13 /8
x"= -24 /8
x"= -3

S={1/4, -3}

Answer 2

Δ= b²-4ac
Δ= 11²-4•4•(-3)
Δ= 121 +48
Δ= 169

X=-b+-√Δ
_________
2a

X=-11+-√169
__________
2•4

X=-11+-13
_________

8

X1=-11+13/8=0.25

X2=-11-13/8=-3

{0.25; -3}