Question

formula bhaskara x² -8x + 12 = 0

Answer 1

Resposta:

$delta = {( - 8)}^{2} - 4 \times 1 \times 12$

$delta = 64 - 48 = 16$

$x = \frac{ - ( - 8) + - \sqrt{16} }{2 \times 1}$

$x = \frac{8 + - 4}{2}$

$x = 6 \: ou \: x = 2$