Question

formula bhaskara 10x²+3x-1=0 resolva ae pessoal pf

Answer 1

∆=b²-4ac
∆=9- 4.10.(-1)
∆=9+40= 49

x=-b±√∆ : 2.a
x=-3±√49 : 2. 10
x'=-3+7/ 20
x'= 4/20= 0,2

x"=-3 -7/ 20
x"=-10/ 20= -0,5