Question

Forme uma Progressão Aritmética (P. A.) de 10 termos com a1 = 3, razão (r) = 3.​

Answer 1

Resposta:

$\boxed{P,A= {1,4,7,10,13,16,19,22,25,28}}$

Explicação passo-a-passo:

$\boxed{a_{n}=a_{1}+(n-1)\cdot\;r}\\[0,15cm]a_{1}=1;\;r=3;\;n=10\\a_{n}=a_{1}+(n-1)\cdot\;r\\\text{Substituindo \cdots }\\a_{10}=1+(10-1)\cdot3\\[0,15cm]a_{10}=1+9\cdot3\\[0,15cm]a_{10}=1+27\\[0,15cm]a_{10}=\boxed{28}\\[0,15cm]\boxed{P,A= {1,4,7,10,13,16,19,22,25,28}}$