Question

forma trigonometrica de z= 1+ rais de 3i

Answer 1

Z = 1 + √3 i
ρ = √(a² + b²
ρ = √[1² +(√3)²]
ρ = √(1 + 3)
ρ = 2
cosθ = a/ρ  e senθ = b/ρ
cosθ = 1/2  e senθ = √3/2   => θ = 60° = 60π/180 = π/3

Z = ρ(cosθ + isenθ)
Z = 2[cos(π/3) + isen(π/3)]