Question

forma de bhaskara4) 2x² - 8x + 6 = 0

Answer 1

Resposta:

S= { 1, 3}

Explicação passo-a-passo:

$2x^2 -8x+6=0\\\\delta= b^2-4.a.c\\delta=(-8)^2-4.2.6\\delta=64-48\\delta=16\\\\x'=-b+\sqrt{delta} /2a\\x'=-(-8)+\sqrt{16} /2.2\\x'=8+4/4\\x'=3\\\\x''=-b-\sqrt{delta} /2a\\x''=-(-8)-\sqrt{16} /2.2\\x''= 8-4/4\\x''=1$