(FMP-RS/PROCEMPA, 2012). As raízes da equação x² + x - 2 = 0 são:
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Boa noite Rafael!
Solução!
![x^{2} +x-2=0\\\\
a=1\\\\
b=1\\\\
c=-2\\\\\\\\\
Formula!\\\\\\\\
x= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{1^{2}-4.1.-2 } }{2.1}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{1+8 } }{2}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{9 } }{2}\\\\\\\\\
x= \dfrac{-1\pm 3 }{2}\\\\\\\\\](https://tex.z-dn.net/?f=+x%5E%7B2%7D+%2Bx-2%3D0%5C%5C%5C%5C%0Aa%3D1%5C%5C%5C%5C%0Ab%3D1%5C%5C%5C%5C%0Ac%3D-2%5C%5C%5C%5C%5C%5C%5C%5C%5C%0AFormula%21%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E%7B2%7D-4.a.c+%7D+%7D%7B2.a%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-1%5Cpm+%5Csqrt%7B1%5E%7B2%7D-4.1.-2+%7D+%7D%7B2.1%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-1%5Cpm+%5Csqrt%7B1%2B8+%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-1%5Cpm+%5Csqrt%7B9+%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-1%5Cpm+3+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A+%0A+ "x^{2} +x-2=0\\\\
a=1\\\\
b=1\\\\
c=-2\\\\\\\\\
Formula!\\\\\\\\
x= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{1^{2}-4.1.-2 } }{2.1}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{1+8 } }{2}\\\\\\\\\
x= \dfrac{-1\pm \sqrt{9 } }{2}\\\\\\\\\
x= \dfrac{-1\pm 3 }{2}\\\\\\\\\")
![Raizes!\\\\\
x_{1} = \dfrac{-1+3}{2}= \dfrac{2}{2}=1\\\\\\
x_{2} = \dfrac{-1-3}{2}= \dfrac{-4}{2}=-2\\\\\\\\\\\](https://tex.z-dn.net/?f=Raizes%21%5C%5C%5C%5C%5C%0A+x_%7B1%7D+%3D+%5Cdfrac%7B-1%2B3%7D%7B2%7D%3D+%5Cdfrac%7B2%7D%7B2%7D%3D1%5C%5C%5C%5C%5C%5C+%0Ax_%7B2%7D+%3D+%5Cdfrac%7B-1-3%7D%7B2%7D%3D+%5Cdfrac%7B-4%7D%7B2%7D%3D-2%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A "Raizes!\\\\\
x_{1} = \dfrac{-1+3}{2}= \dfrac{2}{2}=1\\\\\\
x_{2} = \dfrac{-1-3}{2}= \dfrac{-4}{2}=-2\\\\\\\\\\\")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
Respondido por
0
Olá,
Resolução :
x² + x - 2 = 0
a = 1
b = 1
c = -2
Δ = b² -4ac
Δ = 1² - 4.1.(-2)
Δ = 1 -4.(-2)
Δ = 1 + 8
Δ = 9
x = - b ± √Δ /2a
x = - 1 ± √9 /2 . 1
x = -1 ± 3 /2
x' = -1 + 3/2 = 2/2 = 1
x'' = -1 - 3/2 = -4/2 = -2
S = {-2,1}
Bons Estudos!!
Resolução :
x² + x - 2 = 0
a = 1
b = 1
c = -2
Δ = b² -4ac
Δ = 1² - 4.1.(-2)
Δ = 1 -4.(-2)
Δ = 1 + 8
Δ = 9
x = - b ± √Δ /2a
x = - 1 ± √9 /2 . 1
x = -1 ± 3 /2
x' = -1 + 3/2 = 2/2 = 1
x'' = -1 - 3/2 = -4/2 = -2
S = {-2,1}
Bons Estudos!!
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