Question

FÍSICA transforme 19°c em farenheit e kelwin ​

Answer 1

Boa tarde!

$\frac{c}{5} = \frac{f - 32}{9}$

$\frac{19}{5} = \frac{f - 32}{9}$

5f -160 = 171

5f = 171+160

5f = 331

f = 331/5

f= 66,2°f

k= c +273.15

k = 19+273.15

k= 292.15k

abraços

Answer 2

c / 5 = f - 32/9

19/5 = f - 32/9

19 x 9 = 5 (F - 32)

171 = 5F - 160

171+160 - 5F

331 - 5F

F = 66,2°F

19°C + 273,15 = 292,15 K