Question

FÍSICA HELP HELP HELP​

Answer 1

Resposta:

$f = \frac{k.q1.q2}{ {d}^{2} }$

$f = \frac{9 \times {10}^{9} \times 1 \times {10}^{ - 6} \times 6 \times {10}^{ - 6} }{ {0.7}^{2} }$

$f = \frac{54 \times {10}^{ - 3} }{ 0.49}$

$f = \frac{5400 \times {10}^{ - 3} }{ 49}$

$f = \frac{5.4 }{ 49}$

F =(aproximadamente) 0.11 N

$f = 1.1 \times {10}^{ - 1}$