Question

Find the square root of (3+√5)? ​

Answer 1

Explicação passo-a-passo:

$to \: find \: = > \sqrt{3 + \sqrt{5} } \\ = \sqrt{3 + \sqrt{ \frac{5}{4} } } \\ = \sqrt{ \frac{5}{2} } + \frac{1}{2} + 2 \sqrt{ \frac{5}{2} } \times \frac{1}{2} \\ = \sqrt{( \sqrt{ \frac{5}{2} } } ) ^{2} + ( \sqrt{ \frac{1}{2} } )^{2} + 2 \sqrt{ \frac{5}{2} } \sqrt{ \frac{1}{2} } \\ = \sqrt{( \sqrt{ \frac{5}{2} } } + \sqrt{ \frac{1}{2} } ) ^{2} \\ = ( \sqrt{ \frac{5}{2} } + \sqrt{ \frac{1}{2} } ) .....$