Question

Find the distance between the line 5x-12y-41=0 and the point (3,0)​

Answer 1

Vamos là.

formula:

d = |Ax0 + By0 + C|/√(A² + B²)

A = 5, B = 12, C = -41, x0 = 3, y0 = 0

d = |Ax0 + By0 + C|/√(A² + B²)

d = |15 + 0 - 41|/√(5² + 12²)

d = l-26l/13 = 2