Question

FAZER PELA FORMULA DE BASKARA




a) x² -x = 0
5 15





c) x²-3x+1=0
2 1





d) x²+3x=8
2





e) 1x²=x +8
3 9 3






f) x² = 19x -2
15 15​

Answer 1

A)

x²—x = 0

x(x—1)=0

x=0 V x=1

B)

x²—3x+1=0

Coeficientes:

a=1

b=—3

c=1

Discriminante:

∆ = (-3)²—4•1•1

∆ = 9—4

∆ = 5

Bhaskara:

$\large\boxed{\boxed{{x_{(1,2)}=\frac{-b\pm\sqrt {\Delta}}{2.a}}}}}}}$

$x_{(1,2)}=\frac{3\pm\sqrt{5}}{2.1}$

$\boxed{\begin{array}{Ir}x_{1}=\frac{3-\sqrt{5}}{2}\\\x_{2}=\frac{3+\sqrt{5}}{2}\end{array}}$

C)

• 1x² = x+8
• x²—x—8 = 0

• Coeficientes:
• a = 1
• b = —1
• c = —8

• Discriminante:
• ∆ = b²—4•a•c
• ∆ = (-1)²—4•1•(-8)
• ∆ = 1+32
• ∆ = 33

• Bhaskara:
• x¹'² = (-b±√∆)/2•a
• x¹'² = (1±√33)/2•1
• x¹'² = (1±√33)/2

D)

• x²+3x = 8
• x²+3x—8=0

• Coeficientes:
• a = 1
• b = 3
• c = -8

• Discriminante:
• ∆ = b²—4•a•
• ∆ = 3²—4•1•(-8)
• ∆ = 9+32
• ∆ = 41

• x¹'² = (-b±√∆)/2•a
• x¹'² = (-3±√41)/2•1
• x¹'² = (-2±√41)/2

F)

• x²= 19x—2
• x²—19x+2 = 0

• ∆ = b²—4•a•c
• ∆ = (-19)²—4•1•2
• ∆ = 361—8
• ∆ = 353

• Bhaskara:
• x¹'² = (-b±√∆)/2•a
• x¹'² = (19±√353)/2•1
• x¹'² = (19±√353)/2

Espero ter ajudado bastante!)

Answer 2

Explicação passo-a-passo:

FAZER PELA FORMULA DE BASKARA

a) x² -x = 0

x2-x=0

∆=b2-4.a.c

∆=(-1)2-4.(1).(0)

∆=1

x'=1+1/2=2/2=1

x"=1-1/2=0/2=0

c) x²-3x+1=0

∆=b2-4.a.c

∆=(-3)2-4.(1).(1)

∆=9-4

∆=5

x'=3+√5/2

x"=3-√5/2

d) x²+3x=8

x2+3x-8=0

∆=b2-4.a.c

∆=(3)2-4.(1).(-8)

∆=9+32

∆=41

x'=-3+√41/2

x"=-3-√41/2

e) 1x²=x +8

x2-x-8=0

∆=b2-4.a.c

∆=(-1)2-4.(1).(-8)

∆=1+32

∆=33

x'=1+√33/2

x"=1-√33/2

f) x² = 19x -2

x2-19x+2=0

∆=b2-4.a.c

∆=(-19)2-4.(1).(2)

∆=361-8

∆=357

x'=19+√357/2

x"=19-√357/2