Question

Favor responder a derivada:
y=x^3+( 3x^2+1 /4x)

Answer 1

$y=x^3+\frac{3x^2+1}{4x} \\ \\ y'=3x^2+\frac{3x^2.4x-(3x^2+1).4}{16x^2} \\ \\ \boxed{y'=3x^2+\frac{12x^3-12x^2-4}{16x^2}}$