Question

fatore,por agrupamento os polinomios abaixo

Answer 1

Resposta:

Explicação passo a passo:

a) ax - mx +ay - my => x(a - m) + y(a -m) => (x + y)(a - m)

b) a² + ab + ac + bc => a( a + b) + c(a + b) => (a + c)(a + b)

c) ax - bx + ay - by => a(a - b) + y(a - b) => (a + y)(a - b)

d) ax + 2bx + 3a + 6b=> x(a + 2b) + 3(a + 2b) => (x + 3)(a + 2b)

e) xy + 2x - 2y -4 => x( y + 2) -2(y + 2) => (x -2) (y + 2)

f) 8x² + 4xy + 2x + y => arrumando o polinômio =>

8x² + 2x + 4xy + y => 2x(4x +1) + y(4x +1) => (2x + y)(4x +1)

g) x³ - 5x² + 4x - 20 => x²(x - 5) +4(x - 5) => (x² + 4)(x - 5)

h) abx² + abuy² + a²xy + b²xy =>  arrumando o polinômio =>

abx² + a²xy + abuy² + b²xy => ax(bx + ay) + by(ay + bx) => (ax + by) (ay + bx)

i) 2xy + x + 4y + 2 => x( 2y + 1) + 2(2y + 1) => (x + 2) (2y + 1)

j) x² + 2x + 2y + xy => x(x + 2) + y => (x + y) (2 + x)

k) xy + 2x + 8y + 16 => x( y + 2) + 8( y + 2) => (x + 8) ( y + 2)